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修复 SqlServer 工作单元 bug #23

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需要同时设置 SqlCommand.Connection + Transaction
This commit is contained in:
28810
2019-04-19 13:50:19 +08:00
parent acc1754e2e
commit e3c0f615f9
3 changed files with 15 additions and 4 deletions
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15
FreeSql/Extensions/EntityUtilExtensions.cs
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@ -43,9 +43,7 @@ namespace FreeSql.Extensions.EntityUtil {
for (var a = 0; a < pks.Length; a++) {
var isguid = pks[a].CsType.NullableTypeOrThis() == typeof(Guid);
Expression expthen = null;
if (isguid == false)
expthen = Expression.Assign(var3IsNull, Expression.Constant(true));
else {
if (isguid) {
expthen = Expression.Block(
new Expression[]{
Expression.Assign(Expression.MakeMemberAccess(var1Parm, _table.Properties[pks[a].CsName]), Expression.Call(MethodFreeUtilNewMongodbId)),
@ -55,6 +53,17 @@ namespace FreeSql.Extensions.EntityUtil {
)
}.Where(c => c != null).ToArray()
);
} else if (pks.Length > 1 && pks[a].Attribute.IsIdentity) {
expthen = Expression.Block(
new Expression[]{
a > 0 ? Expression.Call(var2Sb, MethodStringBuilderAppend, Expression.Constant(splitString)) : null,
Expression.Call(var2Sb, MethodStringBuilderAppend,
Expression.Convert(Expression.MakeMemberAccess(var1Parm, _table.Properties[pks[a].CsName]), typeof(object))
)
}.Where(c => c != null).ToArray()
);
} else {
expthen = Expression.Assign(var3IsNull, Expression.Constant(true));
}
if (pks[a].Attribute.IsIdentity || isguid || pks[a].CsType == typeof(string) || pks[a].CsType.IsNullableType()) {
exps.Add(