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	- 修复 $"{a.Code}_{a.Id}" lambda 解析当 {} 多于3个时的 bug(.net 内部机制很坑);
> 3个 {} 时,Arguments[1..3] 解析出来是分开的
> 4个 {} 时,Arguments[1] 只能解析这个出来,然后 [1] 里面是 NewArray []
			
			
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		@@ -369,7 +369,11 @@ namespace FreeSql.PostgreSQL
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                        return _common.StringConcat(exp.Arguments.Select(a => getExp(a)).ToArray(), null);
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                    case "Format":
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                        if (exp.Arguments[0].NodeType != ExpressionType.Constant) throw new Exception($"未实现函数表达式 {exp} 解析,参数 {exp.Arguments[0]} 必须为常量");
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                        var expArgs = exp.Arguments.Where((a, z) => z > 0).Select(a =>
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                        var expArgsHack = exp.Arguments.Count == 2 && exp.Arguments[1].NodeType == ExpressionType.NewArrayInit ?
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                            (exp.Arguments[1] as NewArrayExpression).Expressions : exp.Arguments.Where((a, z) => z > 0);
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                        //3个 {} 时,Arguments 解析出来是分开的
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                        //4个 {} 时,Arguments[1] 只能解析这个出来,然后里面是 NewArray []
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                        var expArgs = expArgsHack.Select(a =>
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                        {
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                            var atype = (a as UnaryExpression)?.Operand.Type.NullableTypeOrThis() ?? a.Type.NullableTypeOrThis();
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                            if (atype == typeof(string)) return $"'||{_common.IsNull(ExpressionLambdaToSql(a, tsc), "''")}||'";
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