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- 修复 $"{a.Code}_{a.Id}" lambda 解析当 {} 多于3个时的 bug(.net 内部机制很坑);
> 3个 {} 时,Arguments[1..3] 解析出来是分开的 > 4个 {} 时,Arguments[1] 只能解析这个出来,然后 [1] 里面是 NewArray []
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@ -338,7 +338,11 @@ namespace FreeSql.Odbc.PostgreSQL
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return _common.StringConcat(exp.Arguments.Select(a => getExp(a)).ToArray(), null);
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case "Format":
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if (exp.Arguments[0].NodeType != ExpressionType.Constant) throw new Exception($"未实现函数表达式 {exp} 解析,参数 {exp.Arguments[0]} 必须为常量");
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var expArgs = exp.Arguments.Where((a, z) => z > 0).Select(a =>
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var expArgsHack = exp.Arguments.Count == 2 && exp.Arguments[1].NodeType == ExpressionType.NewArrayInit ?
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(exp.Arguments[1] as NewArrayExpression).Expressions : exp.Arguments.Where((a, z) => z > 0);
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//3个 {} 时,Arguments 解析出来是分开的
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//4个 {} 时,Arguments[1] 只能解析这个出来,然后里面是 NewArray []
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var expArgs = expArgsHack.Select(a =>
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{
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var atype = (a as UnaryExpression)?.Operand.Type.NullableTypeOrThis() ?? a.Type.NullableTypeOrThis();
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if (atype == typeof(string)) return $"'||{_common.IsNull(ExpressionLambdaToSql(a, tsc), "''")}||'";
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