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- 修复 $"{a.Code}_{a.Id}" lambda 解析当 {} 多于3个时的 bug（.net 内部机制很坑）；

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> 3个 {} 时，Arguments[1..3] 解析出来是分开的
> 4个 {} 时，Arguments[1] 只能解析这个出来，然后 [1] 里面是 NewArray []
This commit is contained in:
28810
2020-07-29 10:59:47 +08:00
parent c2749bad65
commit de86beba4f
30 changed files with 445 additions and 30 deletions
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6
Providers/FreeSql.Provider.MySql/MySqlExpression.cs
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@ -251,7 +251,11 @@ namespace FreeSql.MySql
case "Format":
if (exp.Arguments[0].NodeType != ExpressionType.Constant) throw new Exception($"未实现函数表达式 {exp} 解析，参数 {exp.Arguments[0]} 必须为常量");
if (exp.Arguments.Count == 1) return ExpressionLambdaToSql(exp.Arguments[0], tsc);
var expArgs = exp.Arguments.Where((a, z) => z > 0).Select(a => $"',{_common.IsNull(ExpressionLambdaToSql(a, tsc), "''")},'").ToArray();
var expArgsHack = exp.Arguments.Count == 2 && exp.Arguments[1].NodeType == ExpressionType.NewArrayInit ?
(exp.Arguments[1] as NewArrayExpression).Expressions : exp.Arguments.Where((a, z) => z > 0);
//3个 {} 时，Arguments 解析出来是分开的
//4个 {} 时，Arguments[1] 只能解析这个出来，然后里面是 NewArray []
var expArgs = expArgsHack.Select(a => $"',{_common.IsNull(ExpressionLambdaToSql(a, tsc), "''")},'").ToArray();
return $"concat({string.Format(ExpressionLambdaToSql(exp.Arguments[0], tsc), expArgs)})";
}
}