- 解决 表名名称包含点,无法进行 CRUD 的问题,由于测试的复杂性,此类情况仅支持 MySql/Sqlite CodeFirst 自动迁移;

> 注意:尽量不要使用带点的表名,只有 MySql/Sqlite 对此类表名支持 CodeFirst。但是它不影响 CRUD 功能,使用 [Table(Name = "`sys.config`")] 解决
This commit is contained in:
28810
2020-01-11 02:22:16 +08:00
parent 3fe4c54ee4
commit 994cc475c2
33 changed files with 467 additions and 214 deletions

View File

@ -90,14 +90,14 @@ namespace FreeSql.Odbc.PostgreSQL
var tb = _commonUtils.GetTableByEntity(obj.entityType);
if (tb == null) throw new Exception($"类型 {obj.entityType.FullName} 不可迁移");
if (tb.Columns.Any() == false) throw new Exception($"类型 {obj.entityType.FullName} 不可迁移可迁移属性0个");
var tbname = tb.DbName.Split(new[] { '.' }, 2);
var tbname = _commonUtils.SplitTableName(tb.DbName);
if (tbname?.Length == 1) tbname = new[] { "public", tbname[0] };
var tboldname = tb.DbOldName?.Split(new[] { '.' }, 2); //旧表名
var tboldname = _commonUtils.SplitTableName(tb.DbOldName); //旧表名
if (tboldname?.Length == 1) tboldname = new[] { "public", tboldname[0] };
if (string.IsNullOrEmpty(obj.tableName) == false)
{
var tbtmpname = obj.tableName.Split(new[] { '.' }, 2);
var tbtmpname = _commonUtils.SplitTableName(obj.tableName);
if (tbtmpname?.Length == 1) tbtmpname = new[] { "public", tbtmpname[0] };
if (tbname[0] != tbtmpname[0] || tbname[1] != tbtmpname[1])
{
@ -105,6 +105,7 @@ namespace FreeSql.Odbc.PostgreSQL
tboldname = null;
}
}
//codefirst 不支持表名、模式名、数据库名中带 .
if (string.Compare(tbname[0], "public", true) != 0 && _orm.Ado.ExecuteScalar(CommandType.Text, _commonUtils.FormatSql(" select 1 from pg_namespace where nspname={0}", tbname[0])) == null) //创建模式
sb.Append("CREATE SCHEMA IF NOT EXISTS ").Append(tbname[0]).Append(";\r\n");