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解决变异的 IncludeMany 在多级使用时，无法使用上层的值映射

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This commit is contained in:
28810
2019-05-15 22:14:45 +08:00
parent 1c05852738
commit 93cefb5f92
3 changed files with 145 additions and 42 deletions
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47
FreeSql.Tests/Sqlite/Curd/SqliteSelectTest.cs
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@ -824,6 +824,53 @@ namespace FreeSql.Tests.Sqlite {
.Where(a => a.id <= model1.id)
.ToList();
}
public class TestInclude_OneToManyModel11 {
[Column(IsIdentity = true)]
public int id { get; set; }
public int model2id { get; set; }
public string m3setting { get; set; }
public TestInclude_OneToManyModel22 model2 { get; set; }
public string m1name { get; set; }
}
public class TestInclude_OneToManyModel22 {
[Column(IsIdentity = true)]
public int id { get; set; }
public string m2setting { get; set; }
public List<TestInclude_OneToManyModel33> childs { get; set; }
}
public class TestInclude_OneToManyModel33 {
[Column(IsIdentity = true)]
public int id { get; set; }
public int model2Id { get; set; }
public string title { get; set; }
public string setting { get; set; }
}
[Fact]
public void Include_OneToMany2() {
string setting = "x";
var model2 = new TestInclude_OneToManyModel22 { m2setting = DateTime.Now.Second.ToString() };
model2.id = (int)g.sqlite.Insert(model2).ExecuteIdentity();
var model3s = new[]
{
new TestInclude_OneToManyModel33 {model2Id = model2.id, title = "testmodel3__111", setting = setting},
new TestInclude_OneToManyModel33 {model2Id = model2.id, title = "testmodel3__222", setting = setting},
new TestInclude_OneToManyModel33 {model2Id = model2.id, title = "testmodel3__333", setting = setting}
};
Assert.Equal(3, g.sqlite.Insert(model3s).ExecuteAffrows());
var model1 = new TestInclude_OneToManyModel11 { m1name = DateTime.Now.Second.ToString(), model2id = model2.id, m3setting = setting };
model1.id = (int)g.sqlite.Insert(model1).ExecuteIdentity();
var t1 = g.sqlite.Select<TestInclude_OneToManyModel11>()
.LeftJoin(a => a.model2id == a.model2.id)
.IncludeMany(a => a.model2.childs.Where(m3 => m3.model2Id == a.model2.id && m3.setting == a.m3setting))
.Where(a => a.id == model1.id)
.ToList(true);
}
[Fact]
public void Include_OneToChilds() {
var tag1 = new Tag {