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- 修复 UseGenerateCommandParameterWithLambda 对不可参数化的数据类型冲突的 bug;#1061
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@ -1887,11 +1887,14 @@ namespace FreeSql.Internal
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if (_common.CodeFirst.IsGenerateCommandParameterWithLambda && dbParams != null)
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{
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if (obj == null) return "NULL";
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var paramName = $"exp_{dbParams.Count}";
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if (_common._orm?.Ado.DataType == DataType.GBase) paramName = "?";
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var parm = _common.AppendParamter(dbParams, paramName, mapColumn,
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mapType ?? mapColumn?.Attribute.MapType ?? obj?.GetType(), mapType == null ? obj : Utils.GetDataReaderValue(mapType, obj));
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return _common.QuoteParamterName(paramName);
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var type = mapType ?? mapColumn?.Attribute.MapType ?? obj?.GetType();
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if (_common.CodeFirst.GetDbInfo(type) != null)
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{
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var paramName = $"exp_{dbParams.Count}";
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if (_common._orm?.Ado.DataType == DataType.GBase) paramName = "?";
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var parm = _common.AppendParamter(dbParams, paramName, mapColumn, type, mapType == null ? obj : Utils.GetDataReaderValue(mapType, obj));
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return _common.QuoteParamterName(paramName);
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}
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}
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return string.Format(CultureInfo.InvariantCulture, "{0}", _ado.AddslashesProcessParam(obj, mapType, mapColumn));
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//return string.Concat(_ado.AddslashesProcessParam(obj, mapType, mapColumn));
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