From 59ca312e958e2fc19b912ed513503942b9e87455 Mon Sep 17 00:00:00 2001
From: xuejmnet <326308290@qq.com>
Date: Fri, 10 Feb 2023 08:55:41 +0800
Subject: [PATCH] =?UTF-8?q?=E4=BC=98=E5=8C=96=E5=BD=93props=E5=B1=9E?=
 =?UTF-8?q?=E6=80=A7=E8=BF=87=E5=A4=9A=E6=97=B6=E7=9A=84=E5=88=A4=E6=96=AD?=
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优化当props属性过多时且有过多的属性与prop属性类型一样的时候,只需要迭代到第二次即可判断出是否等于1，无需一直迭代到全属性遍历完
---
 .../CommonProvider/SelectProvider/Select0ProviderReader.cs      | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/FreeSql/Internal/CommonProvider/SelectProvider/Select0ProviderReader.cs b/FreeSql/Internal/CommonProvider/SelectProvider/Select0ProviderReader.cs
index 55ea7502..9ac8cfda 100644
--- a/FreeSql/Internal/CommonProvider/SelectProvider/Select0ProviderReader.cs
+++ b/FreeSql/Internal/CommonProvider/SelectProvider/Select0ProviderReader.cs
@@ -632,7 +632,7 @@ namespace FreeSql.Internal.CommonProvider
                             a.Alias.StartsWith($"{tb.Alias}__") && //开头结尾完全匹配
                             a.Alias.EndsWith($"__{prop.Name}") //不清楚会不会有其他情况 求大佬优化
                             ).FirstOrDefault(); //判断 b > 0 防止 parent 递归关系
-                        if (tb2 == null && props.Where(pw => pw.Value.PropertyType == prop.PropertyType).Count() == 1)
+                        if (tb2 == null && props.Where(pw => pw.Value.PropertyType == prop.PropertyType).Take(2).Count() == 1)
                             tb2 = _tables.Where((a, b) => b > 0 &&
                                 (a.Type == SelectTableInfoType.InnerJoin || a.Type == SelectTableInfoType.LeftJoin || a.Type == SelectTableInfoType.RightJoin) &&
                                 string.IsNullOrEmpty(a.On) == false &&