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- Lambda 参数化功能的 bug 解决
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@ -341,7 +341,7 @@ namespace FreeSql.Tests
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);
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g.sqlserver.CodeFirst.IsGenerateCommandParameterWithLambda = true;
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//g.sqlserver.CodeFirst.IsGenerateCommandParameterWithLambda = true;
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var name = "testname";
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var sdfsdgselect1 = g.sqlserver.Select<TestMySqlStringIsNullable>().Where(a => a.varchar == name);
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var sdfsdgselect2 = g.sqlserver.Select<TestMySqlStringIsNullable>().Where(a => a.varchar == name.SetDbParameter(10));
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@ -37,7 +37,7 @@ public class g
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.UseConnectionString(FreeSql.DataType.SqlServer, "Data Source=.;Integrated Security=True;Initial Catalog=freesqlTest;Pooling=true;Max Pool Size=3")
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//.UseConnectionString(FreeSql.DataType.SqlServer, "Data Source=192.168.164.129;uid=sa;pwd=123456;Initial Catalog=ds_shop;Pooling=true;Max Pool Size=3")
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.UseAutoSyncStructure(true)
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//.UseNoneCommandParameter(true)
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//.UseGenerateCommandParameterWithLambda(true)
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.UseMonitorCommand(
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cmd => Trace.WriteLine(cmd.CommandText), //监听SQL命令对象,在执行前
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(cmd, traceLog) => Console.WriteLine(traceLog))
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