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- 修复 IgnoreColumns 相关方法解析表达式 a => new [] { "Id" .. } 无效的 bug；

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28810
2020-05-10 06:23:00 +08:00
parent a9ee9aa069
commit 54ceefefd2
2 changed files with 17 additions and 3 deletions
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6
FreeSql/Internal/CommonExpression.cs
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@ -341,19 +341,19 @@ namespace FreeSql.Internal
case ExpressionType.Lambda: return ExpressionSelectColumns_MemberAccess_New_NewArrayInit(_tables, (exp as LambdaExpression)?.Body, isQuoteName, getSelectGroupingMapString);
case ExpressionType.Convert: return ExpressionSelectColumns_MemberAccess_New_NewArrayInit(_tables, (exp as UnaryExpression)?.Operand, isQuoteName, getSelectGroupingMapString);
case ExpressionType.Constant: return new[] { ExpressionSelectColumn_MemberAccess(_tables, null, SelectTableInfoType.From, exp, isQuoteName, getSelectGroupingMapString) };
case ExpressionType.MemberAccess: return new[] { ExpressionSelectColumn_MemberAccess(_tables, null, SelectTableInfoType.From, exp, isQuoteName, getSelectGroupingMapString) };
case ExpressionType.MemberAccess: return ExpressionSelectColumn_MemberAccess(_tables, null, SelectTableInfoType.From, exp, isQuoteName, getSelectGroupingMapString).Trim('(', ')', '\'').Split(new[] { "','" }, StringSplitOptions.RemoveEmptyEntries);
case ExpressionType.New:
var newExp = exp as NewExpression;
if (newExp == null) break;
var newExpMembers = new string[newExp.Members.Count];
for (var a = 0; a < newExpMembers.Length; a++) newExpMembers[a] = ExpressionSelectColumn_MemberAccess(_tables, null, SelectTableInfoType.From, newExp.Arguments[a], isQuoteName, getSelectGroupingMapString);
return newExpMembers;
return newExpMembers.Distinct().Select(a => a.Trim('\'')).ToArray();
case ExpressionType.NewArrayInit:
var newArr = exp as NewArrayExpression;
if (newArr == null) break;
var newArrMembers = new List<string>();
foreach (var newArrExp in newArr.Expressions) newArrMembers.AddRange(ExpressionSelectColumns_MemberAccess_New_NewArrayInit(_tables, newArrExp, isQuoteName, getSelectGroupingMapString));
return newArrMembers.ToArray();
return newArrMembers.Distinct().Select(a => a.Trim('\'')).ToArray();
}
return new string[0];
}