fix: 修复ManyToMany不会触发AsTable的bug

This commit is contained in:
xuna 2022-07-29 18:07:11 +08:00
parent b0a9452f97
commit 0f1d811c73

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@ -2352,6 +2352,7 @@ namespace FreeSql.Internal
var mtmReftbname = e.FreeParse(Expression.MakeMemberAccess(memberExp.Expression, exp3Tb.Properties[exp3Tb.ColumnsByPosition[0].CsName])); var mtmReftbname = e.FreeParse(Expression.MakeMemberAccess(memberExp.Expression, exp3Tb.Properties[exp3Tb.ColumnsByPosition[0].CsName]));
mtmReftbname = mtmReftbname.Substring(0, mtmReftbname.Length - commonExp._common.QuoteSqlName(exp3Tb.ColumnsByPosition[0].Attribute.Name).Length - 1); mtmReftbname = mtmReftbname.Substring(0, mtmReftbname.Length - commonExp._common.QuoteSqlName(exp3Tb.ColumnsByPosition[0].Attribute.Name).Length - 1);
var midSelect = commonExp._common._orm.Select<object>().As($"M{select._tables[0].Alias}_M{mtmReftbname}").AsType(memberTbref.RefMiddleEntityType) as Select1Provider<object>; var midSelect = commonExp._common._orm.Select<object>().As($"M{select._tables[0].Alias}_M{mtmReftbname}").AsType(memberTbref.RefMiddleEntityType) as Select1Provider<object>;
select._tableRules.ForEach(o => midSelect.AsTable(o));
switch (commonExp._ado.DataType) switch (commonExp._ado.DataType)
{ {
case DataType.Oracle: case DataType.Oracle: